src/jiangly/ds/01A-Fenwick.hpp

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• Last update: 2025-02-17 23:08:47+08:00
• Include: #include "src/jiangly/ds/01A-Fenwick.hpp"
• Link: https://ac.nowcoder.com/acm/contest/view-submission?submissionId=63382128

Code

/**   树状数组（Fenwick 旧版）
 *    2023-08-11: https://ac.nowcoder.com/acm/contest/view-submission?submissionId=63382128
**/
template <typename T>
struct Fenwick {
    int n;
    std::vector<T> a;
    
    Fenwick(int n = 0) {
        init(n);
    }
    
    void init(int n) {
        this->n = n;
        a.assign(n, T());
    }
    
    void add(int x, T v) {
        for (int i = x + 1; i <= n; i += i & -i) {
            a[i - 1] += v;
        }
    }
    
    T sum(int x) {
        auto ans = T();
        for (int i = x; i > 0; i -= i & -i) {
            ans += a[i - 1];
        }
        return ans;
    }
    
    T rangeSum(int l, int r) {
        return sum(r) - sum(l);
    }
    
    int kth(T k) {
        int x = 0;
        for (int i = 1 << std::__lg(n); i; i /= 2) {
            if (x + i <= n && k >= a[x + i - 1]) {
                x += i;
                k -= a[x - 1];
            }
        }
        return x;
    }
};

#line 1 "src/jiangly/ds/01A-Fenwick.hpp"
/**   树状数组（Fenwick 旧版）
 *    2023-08-11: https://ac.nowcoder.com/acm/contest/view-submission?submissionId=63382128
**/
template <typename T>
struct Fenwick {
    int n;
    std::vector<T> a;
    
    Fenwick(int n = 0) {
        init(n);
    }
    
    void init(int n) {
        this->n = n;
        a.assign(n, T());
    }
    
    void add(int x, T v) {
        for (int i = x + 1; i <= n; i += i & -i) {
            a[i - 1] += v;
        }
    }
    
    T sum(int x) {
        auto ans = T();
        for (int i = x; i > 0; i -= i & -i) {
            ans += a[i - 1];
        }
        return ans;
    }
    
    T rangeSum(int l, int r) {
        return sum(r) - sum(l);
    }
    
    int kth(T k) {
        int x = 0;
        for (int i = 1 << std::__lg(n); i; i /= 2) {
            if (x + i <= n && k >= a[x + i - 1]) {
                x += i;
                k -= a[x - 1];
            }
        }
        return x;
    }
};

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